Base | Representation |
---|---|
bin | 1010000110001110111101… |
… | …0110110010011010110101 |
3 | 1110022100202012002200202121 |
4 | 2201203233112302122311 |
5 | 2423344312033034143 |
6 | 35340141352435541 |
7 | 2224052100214642 |
oct | 241435726623265 |
9 | 43270665080677 |
10 | 11102211221173 |
11 | 35a046a889226 |
12 | 12b38240a8bb1 |
13 | 626c1b093797 |
14 | 2a54c8154dc9 |
15 | 143bd9aca7ed |
hex | a18ef5b26b5 |
11102211221173 has 2 divisors, whose sum is σ = 11102211221174. Its totient is φ = 11102211221172.
The previous prime is 11102211221161. The next prime is 11102211221203. The reversal of 11102211221173 is 37112211220111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11024405371204 + 77805849969 = 3320302^2 + 278937^2 .
It is a cyclic number.
It is not a de Polignac number, because 11102211221173 - 25 = 11102211221141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102211221573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551105610586 + 5551105610587.
It is an arithmetic number, because the mean of its divisors is an integer number (5551105610587).
Almost surely, 211102211221173 is an apocalyptic number.
It is an amenable number.
11102211221173 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102211221173 is an equidigital number, since it uses as much as digits as its factorization.
11102211221173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 25.
Adding to 11102211221173 its reverse (37112211220111), we get a palindrome (48214422441284).
The spelling of 11102211221173 in words is "eleven trillion, one hundred two billion, two hundred eleven million, two hundred twenty-one thousand, one hundred seventy-three".
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