Search a number
-
+
11102212131320 = 235192912710093931
BaseRepresentation
bin1010000110001110111101…
…1010010000100111111000
31110022100202020210221020202
42201203233122100213320
52423344312301200240
635340141424141332
72224052111025302
oct241435732204770
943270666727222
1011102212131320
1135a0470350012
1212b3824467848
13626c1b321b2b
142a54c8310972
15143bd9c0a315
hexa18ef6909f8

11102212131320 has 256 divisors, whose sum is σ = 27449763840000. Its totient is φ = 4025076572160.

The previous prime is 11102212131313. The next prime is 11102212131337. The reversal of 11102212131320 is 2313121220111.

11102212131320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×111022121313202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 11102212131292 and 11102212131301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2824269755 + ... + 2824273685.

It is an arithmetic number, because the mean of its divisors is an integer number (107225640000).

Almost surely, 211102212131320 is an apocalyptic number.

11102212131320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11102212131320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13724881920000).

11102212131320 is an abundant number, since it is smaller than the sum of its proper divisors (16347551708680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11102212131320 is a wasteful number, since it uses less digits than its factorization.

11102212131320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5126 (or 5122 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11102212131320 its reverse (2313121220111), we get a palindrome (13415333351431).

The spelling of 11102212131320 in words is "eleven trillion, one hundred two billion, two hundred twelve million, one hundred thirty-one thousand, three hundred twenty".