Base | Representation |
---|---|
bin | 1010000110001111000000… |
… | …0000010101000110110001 |
3 | 1110022100202221120222000012 |
4 | 2201203300000111012301 |
5 | 2423344322330024103 |
6 | 35340142422104305 |
7 | 2224052261612105 |
oct | 241436000250661 |
9 | 43270687528005 |
10 | 11102222111153 |
11 | 35a0475a47008 |
12 | 12b382787b095 |
13 | 626c20407464 |
14 | 2a54c978b905 |
15 | 143bdaa2c2d8 |
hex | a18f00151b1 |
11102222111153 has 2 divisors, whose sum is σ = 11102222111154. Its totient is φ = 11102222111152.
The previous prime is 11102222111129. The next prime is 11102222111207. The reversal of 11102222111153 is 35111122220111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7199653469089 + 3902568642064 = 2683217^2 + 1975492^2 .
It is a cyclic number.
It is not a de Polignac number, because 11102222111153 - 210 = 11102222110129 is a prime.
It is not a weakly prime, because it can be changed into another prime (11102222111053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551111055576 + 5551111055577.
It is an arithmetic number, because the mean of its divisors is an integer number (5551111055577).
Almost surely, 211102222111153 is an apocalyptic number.
It is an amenable number.
11102222111153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102222111153 is an equidigital number, since it uses as much as digits as its factorization.
11102222111153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 11102222111153 its reverse (35111122220111), we get a palindrome (46213344331264).
The spelling of 11102222111153 in words is "eleven trillion, one hundred two billion, two hundred twenty-two million, one hundred eleven thousand, one hundred fifty-three".
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