Base | Representation |
---|---|
bin | 1010000110001111000000… |
… | …0000010101000111100111 |
3 | 1110022100202221120222002012 |
4 | 2201203300000111013213 |
5 | 2423344322330024312 |
6 | 35340142422104435 |
7 | 2224052261612213 |
oct | 241436000250747 |
9 | 43270687528065 |
10 | 11102222111207 |
11 | 35a0475a47057 |
12 | 12b382787b11b |
13 | 626c204074a6 |
14 | 2a54c978b943 |
15 | 143bdaa2c322 |
hex | a18f00151e7 |
11102222111207 has 2 divisors, whose sum is σ = 11102222111208. Its totient is φ = 11102222111206.
The previous prime is 11102222111153. The next prime is 11102222111221. The reversal of 11102222111207 is 70211122220111.
It is a strong prime.
It is an emirp because it is prime and its reverse (70211122220111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11102222111207 - 212 = 11102222107111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102222111297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551111055603 + 5551111055604.
It is an arithmetic number, because the mean of its divisors is an integer number (5551111055604).
Almost surely, 211102222111207 is an apocalyptic number.
11102222111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102222111207 is an equidigital number, since it uses as much as digits as its factorization.
11102222111207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 11102222111207 its reverse (70211122220111), we get a palindrome (81313344331318).
The spelling of 11102222111207 in words is "eleven trillion, one hundred two billion, two hundred twenty-two million, one hundred eleven thousand, two hundred seven".
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