Base | Representation |
---|---|
bin | 11001001111100101100000… |
… | …000011010011001100100110 |
3 | 112120002121202110220122212001 |
4 | 121033211200003103030212 |
5 | 104022442002101041402 |
6 | 1032042523153515514 |
7 | 32246043064562146 |
oct | 3117454003231446 |
9 | 476077673818761 |
10 | 111022221112102 |
11 | 32414294524543 |
12 | 10550a25272b9a |
13 | 49c4473158931 |
14 | 1d5b70b644926 |
15 | cc7e21bd2187 |
hex | 64f9600d3326 |
111022221112102 has 4 divisors (see below), whose sum is σ = 166533331668156. Its totient is φ = 55511110556050.
The previous prime is 111022221112069. The next prime is 111022221112109. The reversal of 111022221112102 is 201211122220111.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 111022221112102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111022221112109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27755555278024 + ... + 27755555278027.
It is an arithmetic number, because the mean of its divisors is an integer number (41633332917039).
Almost surely, 2111022221112102 is an apocalyptic number.
111022221112102 is a deficient number, since it is larger than the sum of its proper divisors (55511110556054).
111022221112102 is an equidigital number, since it uses as much as digits as its factorization.
111022221112102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55511110556053.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 111022221112102 its reverse (201211122220111), we get a palindrome (312233343332213).
The spelling of 111022221112102 in words is "one hundred eleven trillion, twenty-two billion, two hundred twenty-one million, one hundred twelve thousand, one hundred two".
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