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1110230131312 = 2469389383207
BaseRepresentation
bin10000001001111110110…
…111110110001001110000
310221010200211212021200001
4100021332313312021300
5121142222403200222
62210011020435344
7143132352260161
oct20117667661160
93833624767601
101110230131312
11398933a69075
1215b2059a8b54
138090436c703
143ba42013768
151dd2db6ae27
hex1027edf6270

1110230131312 has 10 divisors (see below), whose sum is σ = 2151070879448. Its totient is φ = 555115065648.

The previous prime is 1110230131303. The next prime is 1110230131319. The reversal of 1110230131312 is 2131310320111.

It is a super-2 number, since 2×11102301313122 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1110230131312.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1110230131319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34694691588 + ... + 34694691619.

Almost surely, 21110230131312 is an apocalyptic number.

It is an amenable number.

1110230131312 is a deficient number, since it is larger than the sum of its proper divisors (1040840748136).

1110230131312 is an equidigital number, since it uses as much as digits as its factorization.

1110230131312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69389383215 (or 69389383209 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1110230131312 its reverse (2131310320111), we get a palindrome (3241540451423).

The spelling of 1110230131312 in words is "one trillion, one hundred ten billion, two hundred thirty million, one hundred thirty-one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 69389383207 138778766414 277557532828 555115065656 1110230131312