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111023131411 is a prime number
BaseRepresentation
bin110011101100101111…
…1101000101100010011
3101121120101121102211001
41213121133220230103
53304333410201121
6123000415002431
711010154021603
oct1473137505423
9347511542731
10111023131411
11430a2732965
1219625509417
13a6144758ca
145533032c03
152d4bd47991
hex19d97e8b13

111023131411 has 2 divisors, whose sum is σ = 111023131412. Its totient is φ = 111023131410.

The previous prime is 111023131399. The next prime is 111023131487. The reversal of 111023131411 is 114131320111.

It is a weak prime.

It is an emirp because it is prime and its reverse (114131320111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111023131411 - 213 = 111023123219 is a prime.

It is a super-2 number, since 2×1110231314112 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111023131511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511565705 + 55511565706.

It is an arithmetic number, because the mean of its divisors is an integer number (55511565706).

Almost surely, 2111023131411 is an apocalyptic number.

111023131411 is a deficient number, since it is larger than the sum of its proper divisors (1).

111023131411 is an equidigital number, since it uses as much as digits as its factorization.

111023131411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 111023131411 its reverse (114131320111), we get a palindrome (225154451522).

The spelling of 111023131411 in words is "one hundred eleven billion, twenty-three million, one hundred thirty-one thousand, four hundred eleven".