Base | Representation |
---|---|
bin | 110101001001011000… |
… | …0011011110100101111 |
3 | 101220121000012210011001 |
4 | 1222102300123310233 |
5 | 3332220104220421 |
6 | 124233050141131 |
7 | 11150165133334 |
oct | 1522260336457 |
9 | 356530183131 |
10 | 114131320111 |
11 | 44448178056 |
12 | 1a1524217a7 |
13 | a9bb3a9c13 |
14 | 5749b5c98b |
15 | 2e7eb5c691 |
hex | 1a92c1bd2f |
114131320111 has 2 divisors, whose sum is σ = 114131320112. Its totient is φ = 114131320110.
The previous prime is 114131320103. The next prime is 114131320123. The reversal of 114131320111 is 111023131411.
It is a weak prime.
It is an emirp because it is prime and its reverse (111023131411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114131320111 - 23 = 114131320103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114131320811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57065660055 + 57065660056.
It is an arithmetic number, because the mean of its divisors is an integer number (57065660056).
Almost surely, 2114131320111 is an apocalyptic number.
114131320111 is a deficient number, since it is larger than the sum of its proper divisors (1).
114131320111 is an equidigital number, since it uses as much as digits as its factorization.
114131320111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 114131320111 its reverse (111023131411), we get a palindrome (225154451522).
The spelling of 114131320111 in words is "one hundred fourteen billion, one hundred thirty-one million, three hundred twenty thousand, one hundred eleven".
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