Base | Representation |
---|---|
bin | 1010000110001111011010… |
… | …0111110001001100001111 |
3 | 1110022101001200110110001112 |
4 | 2201203312213301030033 |
5 | 2423400034234104403 |
6 | 35340201425202235 |
7 | 2224055110246001 |
oct | 241436647611417 |
9 | 43271050413045 |
10 | 11102333113103 |
11 | 35a0522672461 |
12 | 12b3858a9037b |
13 | 626c3a40089b |
14 | 2a54da404371 |
15 | 143be56569d8 |
hex | a18f69f130f |
11102333113103 has 4 divisors (see below), whose sum is σ = 11102349162360. Its totient is φ = 11102317063848.
The previous prime is 11102333113097. The next prime is 11102333113153. The reversal of 11102333113103 is 30131133320111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11102333113103 - 24 = 11102333113087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11102333113153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6937925 + ... + 8386862.
It is an arithmetic number, because the mean of its divisors is an integer number (2775587290590).
Almost surely, 211102333113103 is an apocalyptic number.
11102333113103 is a deficient number, since it is larger than the sum of its proper divisors (16049257).
11102333113103 is an equidigital number, since it uses as much as digits as its factorization.
11102333113103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16049256.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11102333113103 its reverse (30131133320111), we get a palindrome (41233466433214).
The spelling of 11102333113103 in words is "eleven trillion, one hundred two billion, three hundred thirty-three million, one hundred thirteen thousand, one hundred three".
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