11103013111320 has 384 divisors, whose sum is σ = 41135483188800. Its totient is φ = 2577437356032.

The previous prime is 11103013111283. The next prime is 11103013111357. The reversal of 11103013111320 is 2311131030111.

11103013111320 is a `hidden beast` number, since 1 + 1 + 1 + 0 + 30 + 1 + 311 + 1 + 320 = 666.

It is an interprime number because it is at equal distance from previous prime (11103013111283) and next prime (11103013111357).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11103013111293 and 11103013111302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4884702 + ... + 6787218.

Almost surely, 2^{11103013111320} is an apocalyptic number.

11103013111320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11103013111320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20567741594400).

11103013111320 is an abundant number, since it is smaller than the sum of its proper divisors (30032470077480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11103013111320 is a wasteful number, since it uses less digits than its factorization.

11103013111320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1902619 (or 1902612 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11103013111320 its reverse (2311131030111), we get a palindrome (13414144141431).

The spelling of 11103013111320 in words is "eleven trillion, one hundred three billion, thirteen million, one hundred eleven thousand, three hundred twenty".