Base | Representation |
---|---|
bin | 110011101101000010… |
… | …1110001110000011101 |
3 | 101121121002102102022122 |
4 | 1213122011301300131 |
5 | 3304343440130023 |
6 | 123001413152325 |
7 | 11010335014211 |
oct | 1473205616035 |
9 | 347532372278 |
10 | 111033130013 |
11 | 430a8341a73 |
12 | 1962892b6a5 |
13 | a616566940 |
14 | 55344b6941 |
15 | 2d4cb702c8 |
hex | 19da171c1d |
111033130013 has 16 divisors (see below), whose sum is σ = 128342286576. Its totient is φ = 95141744640.
The previous prime is 111033130007. The next prime is 111033130027. The reversal of 111033130013 is 310031330111.
It can be written as a sum of positive squares in 8 ways, for example, as 661672729 + 110371457284 = 25723^2 + 332222^2 .
It is a cyclic number.
It is not a de Polignac number, because 111033130013 - 24 = 111033129997 is a prime.
It is a super-2 number, since 2×1110331300132 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111033129973 and 111033130000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111033130513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3425048 + ... + 3457313.
It is an arithmetic number, because the mean of its divisors is an integer number (8021392911).
Almost surely, 2111033130013 is an apocalyptic number.
111033130013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
111033130013 is a deficient number, since it is larger than the sum of its proper divisors (17309156563).
111033130013 is a wasteful number, since it uses less digits than its factorization.
111033130013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6882464.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 111033130013 its reverse (310031330111), we get a palindrome (421064460124).
The spelling of 111033130013 in words is "one hundred eleven billion, thirty-three million, one hundred thirty thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •