Base | Representation |
---|---|
bin | 1010000110010011000100… |
… | …0101100011111000000101 |
3 | 1110022110121001011201212012 |
4 | 2201210301011203320011 |
5 | 2423404041341021123 |
6 | 35340443025104005 |
7 | 2224121320540454 |
oct | 241446105437005 |
9 | 43273531151765 |
10 | 11103314001413 |
11 | 35a0986322357 |
12 | 12b3a91488005 |
13 | 6270656a8a7a |
14 | 2a55907b8b9b |
15 | 143c51810378 |
hex | a1931163e05 |
11103314001413 has 2 divisors, whose sum is σ = 11103314001414. Its totient is φ = 11103314001412.
The previous prime is 11103314001389. The next prime is 11103314001443. The reversal of 11103314001413 is 31410041330111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10156822398529 + 946491602884 = 3186977^2 + 972878^2 .
It is a cyclic number.
It is not a de Polignac number, because 11103314001413 - 26 = 11103314001349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11103314001443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551657000706 + 5551657000707.
It is an arithmetic number, because the mean of its divisors is an integer number (5551657000707).
Almost surely, 211103314001413 is an apocalyptic number.
It is an amenable number.
11103314001413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11103314001413 is an equidigital number, since it uses as much as digits as its factorization.
11103314001413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 11103314001413 its reverse (31410041330111), we get a palindrome (42513355331524).
The spelling of 11103314001413 in words is "eleven trillion, one hundred three billion, three hundred fourteen million, one thousand, four hundred thirteen".
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