1110441312403 has 4 divisors (see below), whose sum is σ = 1158721369488. Its totient is φ = 1062161255320.

The previous prime is 1110441312391. The next prime is 1110441312413. The reversal of 1110441312403 is 3042131440111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110441312403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1110441312413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24140028508 + ... + 24140028553.

It is an arithmetic number, because the mean of its divisors is an integer number (289680342372).

Almost surely, 2^{1110441312403} is an apocalyptic number.

1110441312403 is a deficient number, since it is larger than the sum of its proper divisors (48280057085).

1110441312403 is an equidigital number, since it uses as much as digits as its factorization.

1110441312403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48280057084.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1110441312403 its reverse (3042131440111), we get a palindrome (4152572752514).

The spelling of 1110441312403 in words is "one trillion, one hundred ten billion, four hundred forty-one million, three hundred twelve thousand, four hundred three".