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11110000000013 is a prime number
BaseRepresentation
bin1010000110101011111110…
…0110100111110000001101
31110100002212000001122200222
42201222333212213300031
52424011240000000023
635343510305201125
72224446104563655
oct241527746476015
943302760048628
1011110000000013
1135a37a73aa032
1212b52386301a5
1362788c920c65
142a5a26759365
15143ee37a1cc8
hexa1abf9a7c0d

11110000000013 has 2 divisors, whose sum is σ = 11110000000014. Its totient is φ = 11110000000012.

The previous prime is 11110000000009. The next prime is 11110000000063. The reversal of 11110000000013 is 31000000001111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10768386636484 + 341613363529 = 3281522^2 + 584477^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110000000013 - 22 = 11110000000009 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11110000000063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000000006 + 5555000000007.

It is an arithmetic number, because the mean of its divisors is an integer number (5555000000007).

Almost surely, 211110000000013 is an apocalyptic number.

It is an amenable number.

11110000000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110000000013 is an equidigital number, since it uses as much as digits as its factorization.

11110000000013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 11110000000013 its reverse (31000000001111), we get a palindrome (42110000001124).

The spelling of 11110000000013 in words is "eleven trillion, one hundred ten billion, thirteen", and thus it is an aban number.