Base | Representation |
---|---|
bin | 1010000110101011111110… |
… | …0110100111110001100111 |
3 | 1110100002212000001122211022 |
4 | 2201222333212213301213 |
5 | 2424011240000000403 |
6 | 35343510305201355 |
7 | 2224446104564144 |
oct | 241527746476147 |
9 | 43302760048738 |
10 | 11110000000103 |
11 | 35a37a73aa104 |
12 | 12b523863025b |
13 | 62788c921004 |
14 | 2a5a267593cb |
15 | 143ee37a1d38 |
hex | a1abf9a7c67 |
11110000000103 has 2 divisors, whose sum is σ = 11110000000104. Its totient is φ = 11110000000102.
The previous prime is 11110000000081. The next prime is 11110000000117. The reversal of 11110000000103 is 30100000001111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11110000000103 - 216 = 11109999934567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11110000000133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000000051 + 5555000000052.
It is an arithmetic number, because the mean of its divisors is an integer number (5555000000052).
Almost surely, 211110000000103 is an apocalyptic number.
11110000000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110000000103 is an equidigital number, since it uses as much as digits as its factorization.
11110000000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 8.
Adding to 11110000000103 its reverse (30100000001111), we get a palindrome (41210000001214).
The spelling of 11110000000103 in words is "eleven trillion, one hundred ten billion, one hundred three", and thus it is an aban number.
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