111100001011213 has 2 divisors, whose sum is σ = 111100001011214. Its totient is φ = 111100001011212.

The previous prime is 111100001011093. The next prime is 111100001011249. The reversal of 111100001011213 is 312110100001111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75202144454889 + 35897856556324 = 8671917^2 + 5991482^2 .

It is an emirp because it is prime and its reverse (312110100001111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111100001011213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111100001011193 and 111100001011202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111100001014213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550000505606 + 55550000505607.

It is an arithmetic number, because the mean of its divisors is an integer number (55550000505607).

Almost surely, 2^{111100001011213} is an apocalyptic number.

It is an amenable number.

111100001011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

111100001011213 is an equidigital number, since it uses as much as digits as its factorization.

111100001011213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 111100001011213 its reverse (312110100001111), we get a palindrome (423210101012324).

The spelling of 111100001011213 in words is "one hundred eleven trillion, one hundred billion, one million, eleven thousand, two hundred thirteen".