Base | Representation |
---|---|
bin | 1010000110101100000000… |
… | …1101001100010000011011 |
3 | 1110100002212201002100101002 |
4 | 2201223000031030100123 |
5 | 2424011300042023003 |
6 | 35343511310015215 |
7 | 2224446256535036 |
oct | 241530015142033 |
9 | 43302781070332 |
10 | 11110010111003 |
11 | 35a3802085621 |
12 | 12b523baa750b |
13 | 627891a511ab |
14 | 2a5a27c2c01d |
15 | 143ee45eca88 |
hex | a1ac034c41b |
11110010111003 has 2 divisors, whose sum is σ = 11110010111004. Its totient is φ = 11110010111002.
The previous prime is 11110010110961. The next prime is 11110010111041. The reversal of 11110010111003 is 30011101001111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11110010111003 - 212 = 11110010106907 is a prime.
It is not a weakly prime, because it can be changed into another prime (11110010111093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005055501 + 5555005055502.
It is an arithmetic number, because the mean of its divisors is an integer number (5555005055502).
Almost surely, 211110010111003 is an apocalyptic number.
11110010111003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110010111003 is an equidigital number, since it uses as much as digits as its factorization.
11110010111003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 11110010111003 its reverse (30011101001111), we get a palindrome (41121111112114).
The spelling of 11110010111003 in words is "eleven trillion, one hundred ten billion, ten million, one hundred eleven thousand, three".
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