Base | Representation |
---|---|
bin | 10000001010101100110… |
… | …100111001101000101001 |
3 | 10221012200120121010002022 |
4 | 100022230310321220221 |
5 | 121200312241023311 |
6 | 2210215321314225 |
7 | 143160433425461 |
oct | 20125464715051 |
9 | 3835616533068 |
10 | 1111001111081 |
11 | 39919a188634 |
12 | 15b3a0035975 |
13 | 809c8001564 |
14 | 3bab6586ba1 |
15 | 1dd766ae5db |
hex | 102acd39a29 |
1111001111081 has 2 divisors, whose sum is σ = 1111001111082. Its totient is φ = 1111001111080.
The previous prime is 1111001111071. The next prime is 1111001111159. The reversal of 1111001111081 is 1801111001111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 662758810000 + 448242301081 = 814100^2 + 669509^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111001111081 is a prime.
It is a super-3 number, since 3×11110011110813 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1111001111021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555500555540 + 555500555541.
It is an arithmetic number, because the mean of its divisors is an integer number (555500555541).
Almost surely, 21111001111081 is an apocalyptic number.
It is an amenable number.
1111001111081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111001111081 is an equidigital number, since it uses as much as digits as its factorization.
1111001111081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 17.
Adding to 1111001111081 its reverse (1801111001111), we get a palindrome (2912112112192).
The spelling of 1111001111081 in words is "one trillion, one hundred eleven billion, one million, one hundred eleven thousand, eighty-one".
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