111100200211111 has 4 divisors (see below), whose sum is σ = 111664160618472. Its totient is φ = 110536239803752.

The previous prime is 111100200211069. The next prime is 111100200211123. The reversal of 111100200211111 is 111112002001111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111100200211111 - 2¹⁵ = 111100200178343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111100200211091 and 111100200211100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111100200211151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281980203385 + ... + 281980203778.

It is an arithmetic number, because the mean of its divisors is an integer number (27916040154618).

Almost surely, 2^{111100200211111} is an apocalyptic number.

111100200211111 is a deficient number, since it is larger than the sum of its proper divisors (563960407361).

111100200211111 is an equidigital number, since it uses as much as digits as its factorization.

111100200211111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 563960407360.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 111100200211111 its reverse (111112002001111), we get a palindrome (222212202212222).

The spelling of 111100200211111 in words is "one hundred eleven trillion, one hundred billion, two hundred million, two hundred eleven thousand, one hundred eleven".