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1111011101113 is a prime number
BaseRepresentation
bin10000001010101101011…
…011000000100110111001
310221012201021101122211111
4100022231123000212321
5121200322320213423
62210220315400321
7143160614354104
oct20125533004671
93835637348744
101111011101113
113991a4891261
1215b3a34530a1
13809ca0bb714
143bab7a2773b
151dd774d460d
hex102ad6c09b9

1111011101113 has 2 divisors, whose sum is σ = 1111011101114. Its totient is φ = 1111011101112.

The previous prime is 1111011101089. The next prime is 1111011101117. The reversal of 1111011101113 is 3111011101111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 645181645824 + 465829455289 = 803232^2 + 682517^2 .

It is an emirp because it is prime and its reverse (3111011101111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111011101113 - 237 = 973572147641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111011101093 and 1111011101102.

It is not a weakly prime, because it can be changed into another prime (1111011101117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555505550556 + 555505550557.

It is an arithmetic number, because the mean of its divisors is an integer number (555505550557).

Almost surely, 21111011101113 is an apocalyptic number.

It is an amenable number.

1111011101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111011101113 is an equidigital number, since it uses as much as digits as its factorization.

1111011101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 1111011101113 its reverse (3111011101111), we get a palindrome (4222022202224).

The spelling of 1111011101113 in words is "one trillion, one hundred eleven billion, eleven million, one hundred one thousand, one hundred thirteen".