1111011121313 has 4 divisors (see below), whose sum is σ = 1111107986688. Its totient is φ = 1110914255940.

The previous prime is 1111011121301. The next prime is 1111011121343. The reversal of 1111011121313 is 3131211101111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1111011121313 - 2¹⁸ = 1111010859169 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111011121291 and 1111011121300.

It is not an unprimeable number, because it can be changed into a prime (1111011121343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48415481 + ... + 48438422.

It is an arithmetic number, because the mean of its divisors is an integer number (277776996672).

Almost surely, 2^{1111011121313} is an apocalyptic number.

It is an amenable number.

1111011121313 is a deficient number, since it is larger than the sum of its proper divisors (96865375).

1111011121313 is an equidigital number, since it uses as much as digits as its factorization.

1111011121313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96865374.

The product of its (nonzero) digits is 18, while the sum is 17.

Adding to 1111011121313 its reverse (3131211101111), we get a palindrome (4242222222424).

The spelling of 1111011121313 in words is "one trillion, one hundred eleven billion, eleven million, one hundred twenty-one thousand, three hundred thirteen".