1111021120121 has 4 divisors (see below), whose sum is σ = 1212023040144. Its totient is φ = 1010019200100.

The previous prime is 1111021120003. The next prime is 1111021120133. The reversal of 1111021120121 is 1210211201111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111021120121 is a prime.

It is a super-2 number, since 2×1111021120121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111021120096 and 1111021120105.

It is not an unprimeable number, because it can be changed into a prime (1111021150121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50500959995 + ... + 50500960016.

It is an arithmetic number, because the mean of its divisors is an integer number (303005760036).

Almost surely, 2^{1111021120121} is an apocalyptic number.

1111021120121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1111021120121 is a deficient number, since it is larger than the sum of its proper divisors (101001920023).

1111021120121 is a wasteful number, since it uses less digits than its factorization.

1111021120121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101001920022.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 1111021120121 its reverse (1210211201111), we get a palindrome (2321232321232).

The spelling of 1111021120121 in words is "one trillion, one hundred eleven billion, twenty-one million, one hundred twenty thousand, one hundred twenty-one".