111104555141 has 2 divisors, whose sum is σ = 111104555142. Its totient is φ = 111104555140.

The previous prime is 111104555123. The next prime is 111104555143. The reversal of 111104555141 is 141555401111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84387345025 + 26717210116 = 290495^2 + 163454^2 .

It is a cyclic number.

It is not a de Polignac number, because 111104555141 - 2¹⁸ = 111104292997 is a prime.

Together with 111104555143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111104555143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55552277570 + 55552277571.

It is an arithmetic number, because the mean of its divisors is an integer number (55552277571).

Almost surely, 2^111104555141 is an apocalyptic number.

It is an amenable number.

111104555141 is a deficient number, since it is larger than the sum of its proper divisors (1).

111104555141 is an equidigital number, since it uses as much as digits as its factorization.

111104555141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2000, while the sum is 29.

Adding to 111104555141 its reverse (141555401111), we get a palindrome (252659956252).

The spelling of 111104555141 in words is "one hundred eleven billion, one hundred four million, five hundred fifty-five thousand, one hundred forty-one".