1111100034113 has 4 divisors (see below), whose sum is σ = 1115526727728. Its totient is φ = 1106673340500.

The previous prime is 1111100034101. The next prime is 1111100034127. The reversal of 1111100034113 is 3114300011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1111100034113 - 2⁶ = 1111100034049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1111100034091 and 1111100034100.

It is not an unprimeable number, because it can be changed into a prime (1111100094113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2213346431 + ... + 2213346932.

It is an arithmetic number, because the mean of its divisors is an integer number (278881681932).

Almost surely, 2^{1111100034113} is an apocalyptic number.

It is an amenable number.

1111100034113 is a deficient number, since it is larger than the sum of its proper divisors (4426693615).

1111100034113 is an equidigital number, since it uses as much as digits as its factorization.

1111100034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4426693614.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1111100034113 its reverse (3114300011111), we get a palindrome (4225400045224).

The spelling of 1111100034113 in words is "one trillion, one hundred eleven billion, one hundred million, thirty-four thousand, one hundred thirteen".