Base | Representation |
---|---|
bin | 11001010000110111010000… |
… | …101011010101011011001111 |
3 | 112120102000100122012021220102 |
4 | 121100313100223111123033 |
5 | 104030411300030013403 |
6 | 1032151122310241315 |
7 | 32255301425042021 |
oct | 3120672053253317 |
9 | 476360318167812 |
10 | 111110010001103 |
11 | 32448544017173 |
12 | 10565a4565623b |
13 | 49cc823b590b9 |
14 | 1d61a78a12011 |
15 | cca35dd99b88 |
hex | 650dd0ad56cf |
111110010001103 has 2 divisors, whose sum is σ = 111110010001104. Its totient is φ = 111110010001102.
The previous prime is 111110010001099. The next prime is 111110010001139. The reversal of 111110010001103 is 301100010011111.
It is a weak prime.
It is an emirp because it is prime and its reverse (301100010011111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111110010001103 - 22 = 111110010001099 is a prime.
It is a super-2 number, since 2×1111100100011032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111112010001103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555005000551 + 55555005000552.
It is an arithmetic number, because the mean of its divisors is an integer number (55555005000552).
Almost surely, 2111110010001103 is an apocalyptic number.
111110010001103 is a deficient number, since it is larger than the sum of its proper divisors (1).
111110010001103 is an equidigital number, since it uses as much as digits as its factorization.
111110010001103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 111110010001103 its reverse (301100010011111), we get a palindrome (412210020012214).
The spelling of 111110010001103 in words is "one hundred eleven trillion, one hundred ten billion, ten million, one thousand, one hundred three".
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