111110010001411 has 2 divisors, whose sum is σ = 111110010001412. Its totient is φ = 111110010001410.

The previous prime is 111110010001391. The next prime is 111110010001421. The reversal of 111110010001411 is 114100010011111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111110010001411 - 2⁵ = 111110010001379 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111110010001391 and 111110010001400.

It is not a weakly prime, because it can be changed into another prime (111110010001421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555005000705 + 55555005000706.

It is an arithmetic number, because the mean of its divisors is an integer number (55555005000706).

Almost surely, 2^{111110010001411} is an apocalyptic number.

111110010001411 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110010001411 is an equidigital number, since it uses as much as digits as its factorization.

111110010001411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 111110010001411 its reverse (114100010011111), we get a palindrome (225210020012522).

The spelling of 111110010001411 in words is "one hundred eleven trillion, one hundred ten billion, ten million, one thousand, four hundred eleven".