1111100103413 has 2 divisors, whose sum is σ = 1111100103414. Its totient is φ = 1111100103412.

The previous prime is 1111100103403. The next prime is 1111100103431. The reversal of 1111100103413 is 3143010011111.

Together with next prime (1111100103431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 565146104644 + 545953998769 = 751762^2 + 738887^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111100103413 - 2³⁰ = 1110026361589 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111100103391 and 1111100103400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111100103403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555550051706 + 555550051707.

It is an arithmetic number, because the mean of its divisors is an integer number (555550051707).

Almost surely, 2^{1111100103413} is an apocalyptic number.

It is an amenable number.

1111100103413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111100103413 is an equidigital number, since it uses as much as digits as its factorization.

1111100103413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1111100103413 its reverse (3143010011111), we get a palindrome (4254110114524).

The spelling of 1111100103413 in words is "one trillion, one hundred eleven billion, one hundred million, one hundred three thousand, four hundred thirteen".