111110021119973 has 2 divisors, whose sum is σ = 111110021119974. Its totient is φ = 111110021119972.

The previous prime is 111110021119969. The next prime is 111110021120011. The reversal of 111110021119973 is 379911120011111.

It is an a-pointer prime, because the next prime (111110021120011) can be obtained adding 111110021119973 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95617751935489 + 15492269184484 = 9778433^2 + 3936022^2 .

It is a cyclic number.

It is not a de Polignac number, because 111110021119973 - 2² = 111110021119969 is a prime.

It is a super-2 number, since 2×111110021119973² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111110021199973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555010559986 + 55555010559987.

It is an arithmetic number, because the mean of its divisors is an integer number (55555010559987).

Almost surely, 2^{111110021119973} is an apocalyptic number.

It is an amenable number.

111110021119973 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110021119973 is an equidigital number, since it uses as much as digits as its factorization.

111110021119973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 38.

The spelling of 111110021119973 in words is "one hundred eleven trillion, one hundred ten billion, twenty-one million, one hundred nineteen thousand, nine hundred seventy-three".