111110100000113 has 2 divisors, whose sum is σ = 111110100000114. Its totient is φ = 111110100000112.

The previous prime is 111110100000089. The next prime is 111110100000149. The reversal of 111110100000113 is 311000001011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88864991873329 + 22245108126784 = 9426823^2 + 4716472^2 .

It is a cyclic number.

It is not a de Polignac number, because 111110100000113 - 2¹⁰ = 111110099999089 is a prime.

It is a super-2 number, since 2×111110100000113² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111110100000094 and 111110100000103.

It is not a weakly prime, because it can be changed into another prime (111110100002113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555050000056 + 55555050000057.

It is an arithmetic number, because the mean of its divisors is an integer number (55555050000057).

Almost surely, 2^{111110100000113} is an apocalyptic number.

It is an amenable number.

111110100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110100000113 is an equidigital number, since it uses as much as digits as its factorization.

111110100000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 111110100000113 its reverse (311000001011111), we get a palindrome (422110101011224).

The spelling of 111110100000113 in words is "one hundred eleven trillion, one hundred ten billion, one hundred million, one hundred thirteen", and thus it is an aban number.