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1111101002012 = 22277775250503
BaseRepresentation
bin10000001010110010110…
…001111101000100011100
310221012221112120002200102
4100022302301331010130
5121201013324031022
62210233250320232
7143163055454621
oct20126261750434
93835845502612
101111101002012
11399240605121
1215b409589078
1380a12907511
143bac594a348
151dd80341a92
hex102b2c7d11c

1111101002012 has 6 divisors (see below), whose sum is σ = 1944426753528. Its totient is φ = 555550501004.

The previous prime is 1111101001987. The next prime is 1111101002059. The reversal of 1111101002012 is 2102001011111.

It is a super-3 number, since 3×11111010020123 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111101001984 and 1111101002002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 138887625248 + ... + 138887625255.

It is an arithmetic number, because the mean of its divisors is an integer number (324071125588).

Almost surely, 21111101002012 is an apocalyptic number.

It is an amenable number.

1111101002012 is a deficient number, since it is larger than the sum of its proper divisors (833325751516).

1111101002012 is a wasteful number, since it uses less digits than its factorization.

1111101002012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 277775250507 (or 277775250505 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1111101002012 its reverse (2102001011111), we get a palindrome (3213102013123).

Subtracting 1111101002012 from its reverse (2102001011111), we obtain a palindrome (990900009099).

The spelling of 1111101002012 in words is "one trillion, one hundred eleven billion, one hundred one million, two thousand, twelve".

Divisors: 1 2 4 277775250503 555550501006 1111101002012