Base | Representation |
---|---|
bin | 10000001010110010110… |
… | …001111111100010011001 |
3 | 10221012221112120121112211 |
4 | 100022302301333202121 |
5 | 121201013324341441 |
6 | 2210233250435121 |
7 | 143163055526242 |
oct | 20126261774231 |
9 | 3835845517484 |
10 | 1111101012121 |
11 | 399240611781 |
12 | 15b409592aa1 |
13 | 80a1290bcb9 |
14 | 3bac594dcc9 |
15 | 1dd80344a81 |
hex | 102b2c7f899 |
1111101012121 has 2 divisors, whose sum is σ = 1111101012122. Its totient is φ = 1111101012120.
The previous prime is 1111101012113. The next prime is 1111101012137. The reversal of 1111101012121 is 1212101011111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 595273971600 + 515827040521 = 771540^2 + 718211^2 .
It is an emirp because it is prime and its reverse (1212101011111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111101012121 - 23 = 1111101012113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111101012191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555550506060 + 555550506061.
It is an arithmetic number, because the mean of its divisors is an integer number (555550506061).
Almost surely, 21111101012121 is an apocalyptic number.
It is an amenable number.
1111101012121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111101012121 is an equidigital number, since it uses as much as digits as its factorization.
1111101012121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 1111101012121 its reverse (1212101011111), we get a palindrome (2323202023232).
The spelling of 1111101012121 in words is "one trillion, one hundred eleven billion, one hundred one million, twelve thousand, one hundred twenty-one".
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