11111010221147 has 2 divisors, whose sum is σ = 11111010221148. Its totient is φ = 11111010221146.

The previous prime is 11111010221093. The next prime is 11111010221149. The reversal of 11111010221147 is 74112201011111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111010221147 is a prime.

Together with 11111010221149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11111010221149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555505110573 + 5555505110574.

It is an arithmetic number, because the mean of its divisors is an integer number (5555505110574).

Almost surely, 2^{11111010221147} is an apocalyptic number.

11111010221147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111010221147 is an equidigital number, since it uses as much as digits as its factorization.

11111010221147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 23.

Adding to 11111010221147 its reverse (74112201011111), we get a palindrome (85223211232258).

The spelling of 11111010221147 in words is "eleven trillion, one hundred eleven billion, ten million, two hundred twenty-one thousand, one hundred forty-seven".