Search a number
-
+
111110111212013 is a prime number
BaseRepresentation
bin11001010000110111010110…
…101101011011000111101101
3112120102000121200122100011122
4121100313112231123013231
5104030412001432241023
61032151140323430325
732255304064236404
oct3120672655330755
9476360550570148
10111110111212013
1132448596165451
1210565a735253a5
1349cc83bb04b04
141d61a8823a63b
15cca367bdd2c8
hex650dd6b5b1ed

111110111212013 has 2 divisors, whose sum is σ = 111110111212014. Its totient is φ = 111110111212012.

The previous prime is 111110111211961. The next prime is 111110111212069. The reversal of 111110111212013 is 310212111011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103663308784324 + 7446802427689 = 10181518^2 + 2728883^2 .

It is a cyclic number.

It is not a de Polignac number, because 111110111212013 - 224 = 111110094434797 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111110111211982 and 111110111212000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111110111217013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555055606006 + 55555055606007.

It is an arithmetic number, because the mean of its divisors is an integer number (55555055606007).

Almost surely, 2111110111212013 is an apocalyptic number.

It is an amenable number.

111110111212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110111212013 is an equidigital number, since it uses as much as digits as its factorization.

111110111212013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 17.

Adding to 111110111212013 its reverse (310212111011111), we get a palindrome (421322222223124).

The spelling of 111110111212013 in words is "one hundred eleven trillion, one hundred ten billion, one hundred eleven million, two hundred twelve thousand, thirteen".