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111110131004 = 2227777532751
BaseRepresentation
bin110011101111010101…
…1100000110100111100
3101121210110022110211012
41213132223200310330
53310023143143004
6123013203414352
711012261346665
oct1473653406474
9347713273735
10111110131004
1143137854a54
121964a6843b8
13a6294b6c62
1455407dc36c
152d547d046e
hex19deae0d3c

111110131004 has 6 divisors (see below), whose sum is σ = 194442729264. Its totient is φ = 55555065500.

The previous prime is 111110130959. The next prime is 111110131117. The reversal of 111110131004 is 400131011111.

It is a happy number.

It is a super-3 number, since 3×1111101310043 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 111110131004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13888766372 + ... + 13888766379.

It is an arithmetic number, because the mean of its divisors is an integer number (32407121544).

Almost surely, 2111110131004 is an apocalyptic number.

It is an amenable number.

111110131004 is a deficient number, since it is larger than the sum of its proper divisors (83332598260).

111110131004 is a wasteful number, since it uses less digits than its factorization.

111110131004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27777532755 (or 27777532753 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 111110131004 its reverse (400131011111), we get a palindrome (511241142115).

The spelling of 111110131004 in words is "one hundred eleven billion, one hundred ten million, one hundred thirty-one thousand, four".

Divisors: 1 2 4 27777532751 55555065502 111110131004