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11111030103014 = 25555515051507
BaseRepresentation
bin1010000110101111110100…
…0000001001101111100110
31110100012111210101022100222
42201223331000021233212
52424020342201244024
635344200424004342
72224513453402502
oct241537500115746
943305453338328
1011111030103014
1135a4185913726
1212b54856006b2
136279c516ac6a
142a5ac34a1302
15144053e2c85e
hexa1afd009be6

11111030103014 has 4 divisors (see below), whose sum is σ = 16666545154524. Its totient is φ = 5555515051506.

The previous prime is 11111030103011. The next prime is 11111030103031. The reversal of 11111030103014 is 41030103011111.

11111030103014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11111030102983 and 11111030103001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111030103011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2777757525752 + ... + 2777757525755.

It is an arithmetic number, because the mean of its divisors is an integer number (4166636288631).

Almost surely, 211111030103014 is an apocalyptic number.

11111030103014 is a deficient number, since it is larger than the sum of its proper divisors (5555515051510).

11111030103014 is an equidigital number, since it uses as much as digits as its factorization.

11111030103014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5555515051509.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 11111030103014 its reverse (41030103011111), we get a palindrome (52141133114125).

The spelling of 11111030103014 in words is "eleven trillion, one hundred eleven billion, thirty million, one hundred three thousand, fourteen".

Divisors: 1 2 5555515051507 11111030103014