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11111056003 is a prime number
BaseRepresentation
bin10100101100100010…
…10100001010000011
31001200100102010102201
422112101110022003
5140223412243003
65034312254031
7542225263165
oct122621241203
931610363381
1011111056003
1147919a0913
1221a10a1317
131080c3c568
1477593c935
154506c9b1d
hex296454283

11111056003 has 2 divisors, whose sum is σ = 11111056004. Its totient is φ = 11111056002.

The previous prime is 11111056001. The next prime is 11111056091. The reversal of 11111056003 is 30065011111.

It is a weak prime.

It is an emirp because it is prime and its reverse (30065011111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11111056003 - 21 = 11111056001 is a prime.

Together with 11111056001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11111056001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555528001 + 5555528002.

It is an arithmetic number, because the mean of its divisors is an integer number (5555528002).

Almost surely, 211111056003 is an apocalyptic number.

11111056003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111056003 is an equidigital number, since it uses as much as digits as its factorization.

11111056003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 11111056003 its reverse (30065011111), we get a palindrome (41176067114).

The spelling of 11111056003 in words is "eleven billion, one hundred eleven million, fifty-six thousand, three".