1111110212057 has 2 divisors, whose sum is σ = 1111110212058. Its totient is φ = 1111110212056.

The previous prime is 1111110211997. The next prime is 1111110212059. The reversal of 1111110212057 is 7502120111111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1109954959936 + 1155252121 = 1053544^2 + 33989^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111110212057 - 2¹⁴ = 1111110195673 is a prime.

It is a super-4 number, since 4×1111110212057⁴ (a number of 49 digits) contains 4444 as substring.

Together with 1111110212059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1111110212059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555555106028 + 555555106029.

It is an arithmetic number, because the mean of its divisors is an integer number (555555106029).

Almost surely, 2^{1111110212057} is an apocalyptic number.

It is an amenable number.

1111110212057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111110212057 is an equidigital number, since it uses as much as digits as its factorization.

1111110212057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 140, while the sum is 23.

Adding to 1111110212057 its reverse (7502120111111), we get a palindrome (8613230323168).

The spelling of 1111110212057 in words is "one trillion, one hundred eleven billion, one hundred ten million, two hundred twelve thousand, fifty-seven".