Base | Representation |
---|---|
bin | 10000001010110011100… |
… | …001010010101100001111 |
3 | 10221012222101220120002021 |
4 | 100022303201102230033 |
5 | 121201030013130333 |
6 | 2210234412311011 |
7 | 143163266110465 |
oct | 20126341225417 |
9 | 3835871816067 |
10 | 1111113411343 |
11 | 399247610471 |
12 | 15b411772467 |
13 | 80a15360910 |
14 | 3bac745a835 |
15 | 1dd8149382d |
hex | 102b3852b0f |
1111113411343 has 4 divisors (see below), whose sum is σ = 1196583673768. Its totient is φ = 1025643148920.
The previous prime is 1111113411281. The next prime is 1111113411371. The reversal of 1111113411343 is 3431143111111.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1111113411343 - 221 = 1111111314191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1111113411383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42735131193 + ... + 42735131218.
It is an arithmetic number, because the mean of its divisors is an integer number (299145918442).
Almost surely, 21111113411343 is an apocalyptic number.
1111113411343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1111113411343 is a deficient number, since it is larger than the sum of its proper divisors (85470262425).
1111113411343 is an equidigital number, since it uses as much as digits as its factorization.
1111113411343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85470262424.
The product of its digits is 432, while the sum is 25.
Adding to 1111113411343 its reverse (3431143111111), we get a palindrome (4542256522454).
The spelling of 1111113411343 in words is "one trillion, one hundred eleven billion, one hundred thirteen million, four hundred eleven thousand, three hundred forty-three".
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