Base | Representation |
---|---|
bin | 11001010000111001000111… |
… | …011010101011000100111111 |
3 | 112120102012111110201112002121 |
4 | 121100321013122223010333 |
5 | 104030424340020401142 |
6 | 1032152052112303411 |
7 | 32255401664556553 |
oct | 3120710732530477 |
9 | 476365443645077 |
10 | 111112002122047 |
11 | 32449376572113 |
12 | 10566300841b67 |
13 | 49cca807a50a4 |
14 | 1d61bc7419863 |
15 | cca428c02c67 |
hex | 650e476ab13f |
111112002122047 has 2 divisors, whose sum is σ = 111112002122048. Its totient is φ = 111112002122046.
The previous prime is 111112002122021. The next prime is 111112002122111. The reversal of 111112002122047 is 740221200211111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111112002122047 - 215 = 111112002089279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111112002222047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556001061023 + 55556001061024.
It is an arithmetic number, because the mean of its divisors is an integer number (55556001061024).
Almost surely, 2111112002122047 is an apocalyptic number.
111112002122047 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112002122047 is an equidigital number, since it uses as much as digits as its factorization.
111112002122047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 111112002122047 its reverse (740221200211111), we get a palindrome (851333202333158).
The spelling of 111112002122047 in words is "one hundred eleven trillion, one hundred twelve billion, two million, one hundred twenty-two thousand, forty-seven".
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