Base | Representation |
---|---|
bin | 1010000110110000011100… |
… | …1100111010101001011100 |
3 | 1110100012221201101000102000 |
4 | 2201230013030322221130 |
5 | 2424021220003034322 |
6 | 35344225415402300 |
7 | 2224520632026411 |
oct | 241540714725134 |
9 | 43305851330360 |
10 | 11111201221212 |
11 | 35a426346a324 |
12 | 12b5512983390 |
13 | 627a21752231 |
14 | 2a5adc0c6108 |
15 | 144063e7e3ac |
hex | a1b0733aa5c |
11111201221212 has 384 divisors, whose sum is σ = 31228563744000. Its totient is φ = 3403703255040.
The previous prime is 11111201221207. The next prime is 11111201221313. The reversal of 11111201221212 is 21212210211111.
It is a happy number.
11111201221212 is a `hidden beast` number, since 1 + 111 + 120 + 1 + 221 + 212 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 11960388364 + ... + 11960389292.
It is an arithmetic number, because the mean of its divisors is an integer number (81324384750).
Almost surely, 211111201221212 is an apocalyptic number.
11111201221212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11111201221212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15614281872000).
11111201221212 is an abundant number, since it is smaller than the sum of its proper divisors (20117362522788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11111201221212 is a wasteful number, since it uses less digits than its factorization.
11111201221212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1686 (or 1678 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 11111201221212 its reverse (21212210211111), we get a palindrome (32323411432323).
It can be divided in two parts, 1111120 and 1221212, that added together give a palindrome (2332332).
The spelling of 11111201221212 in words is "eleven trillion, one hundred eleven billion, two hundred one million, two hundred twenty-one thousand, two hundred twelve".
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