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1111121211311 is a prime number
BaseRepresentation
bin10000001010110011111…
…111000010111110101111
310221012222221120211121222
4100022303333002332233
5121201034012230221
62210235251413555
7143163422315066
oct20126377027657
93835887524558
101111121211311
11399250a58721
1215b4142b42bb
1380a16b61c97
143bac84cb1dd
151dd81ed49ab
hex102b3fc2faf

1111121211311 has 2 divisors, whose sum is σ = 1111121211312. Its totient is φ = 1111121211310.

The previous prime is 1111121211271. The next prime is 1111121211323. The reversal of 1111121211311 is 1131121211111.

It is a m-pointer prime, because the next prime (1111121211323) can be obtained adding 1111121211311 to its product of digits (12).

It is a strong prime.

It is an emirp because it is prime and its reverse (1131121211111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111121211311 - 26 = 1111121211247 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1111121211311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111121214311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555560605655 + 555560605656.

It is an arithmetic number, because the mean of its divisors is an integer number (555560605656).

Almost surely, 21111121211311 is an apocalyptic number.

1111121211311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111121211311 is an equidigital number, since it uses as much as digits as its factorization.

1111121211311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12, while the sum is 17.

Adding to 1111121211311 its reverse (1131121211111), we get a palindrome (2242242422422).

The spelling of 1111121211311 in words is "one trillion, one hundred eleven billion, one hundred twenty-one million, two hundred eleven thousand, three hundred eleven".