Base | Representation |
---|---|
bin | 110011101111011010… |
… | …0001110001111111001 |
3 | 101121210121121110210001 |
4 | 1213132310032033321 |
5 | 3310024234223301 |
6 | 123013324353001 |
7 | 11012316636355 |
oct | 1473664161771 |
9 | 347717543701 |
10 | 111112414201 |
11 | 43139074398 |
12 | 1964b3a5761 |
13 | a629b06269 |
14 | 5540c34465 |
15 | 2d54ad1c01 |
hex | 19ded0e3f9 |
111112414201 has 2 divisors, whose sum is σ = 111112414202. Its totient is φ = 111112414200.
The previous prime is 111112414199. The next prime is 111112414243. The reversal of 111112414201 is 102414211111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109361828601 + 1750585600 = 330699^2 + 41840^2 .
It is a cyclic number.
It is not a de Polignac number, because 111112414201 - 21 = 111112414199 is a prime.
Together with 111112414199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (111112414271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556207100 + 55556207101.
It is an arithmetic number, because the mean of its divisors is an integer number (55556207101).
Almost surely, 2111112414201 is an apocalyptic number.
It is an amenable number.
111112414201 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112414201 is an equidigital number, since it uses as much as digits as its factorization.
111112414201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 111112414201 its reverse (102414211111), we get a palindrome (213526625312).
The spelling of 111112414201 in words is "one hundred eleven billion, one hundred twelve million, four hundred fourteen thousand, two hundred one".
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