Base | Representation |
---|---|
bin | 11001010000111001100001… |
… | …101001011100100100111111 |
3 | 112120102020122010210220220002 |
4 | 121100321201221130210333 |
5 | 104030431240200434211 |
6 | 1032152203512544515 |
7 | 32255415620313005 |
oct | 3120714151344477 |
9 | 476366563726802 |
10 | 111112442202431 |
11 | 32449581a2300a |
12 | 105664040b213b |
13 | 49ccb20a0a997 |
14 | 1d61c29a54a75 |
15 | cca45268203b |
hex | 650e61a5c93f |
111112442202431 has 2 divisors, whose sum is σ = 111112442202432. Its totient is φ = 111112442202430.
The previous prime is 111112442202341. The next prime is 111112442202439. The reversal of 111112442202431 is 134202244211111.
It is a happy number.
Together with previous prime (111112442202341) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (134202244211111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111112442202431 - 218 = 111112441940287 is a prime.
It is a super-2 number, since 2×1111124422024312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111112442202394 and 111112442202403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111112442202439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556221101215 + 55556221101216.
It is an arithmetic number, because the mean of its divisors is an integer number (55556221101216).
Almost surely, 2111112442202431 is an apocalyptic number.
111112442202431 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112442202431 is an equidigital number, since it uses as much as digits as its factorization.
111112442202431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 29.
Adding to 111112442202431 its reverse (134202244211111), we get a palindrome (245314686413542).
The spelling of 111112442202431 in words is "one hundred eleven trillion, one hundred twelve billion, four hundred forty-two million, two hundred two thousand, four hundred thirty-one".
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