11111300202133 has 2 divisors, whose sum is σ = 11111300202134. Its totient is φ = 11111300202132.

The previous prime is 11111300201921. The next prime is 11111300202173. The reversal of 11111300202133 is 33120200311111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6656596081444 + 4454704120689 = 2580038^2 + 2110617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111300202133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11111300202133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111300202173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555650101066 + 5555650101067.

It is an arithmetic number, because the mean of its divisors is an integer number (5555650101067).

Almost surely, 2^{11111300202133} is an apocalyptic number.

It is an amenable number.

11111300202133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111300202133 is an equidigital number, since it uses as much as digits as its factorization.

11111300202133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11111300202133 its reverse (33120200311111), we get a palindrome (44231500513244).

The spelling of 11111300202133 in words is "eleven trillion, one hundred eleven billion, three hundred million, two hundred two thousand, one hundred thirty-three".