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11111302133 is a prime number
BaseRepresentation
bin10100101100100100…
…10000001111110101
31001200100212122001122
422112102100033311
5140223443132013
65034321433325
7542230336601
oct122622201765
931610778048
1011111302133
114792049828
1221a119b845
131080cc75b9
147759a4501
15450727a08
hex2964903f5

11111302133 has 2 divisors, whose sum is σ = 11111302134. Its totient is φ = 11111302132.

The previous prime is 11111302117. The next prime is 11111302157. The reversal of 11111302133 is 33120311111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8549221444 + 2562080689 = 92462^2 + 50617^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111302133 - 24 = 11111302117 is a prime.

It is a super-2 number, since 2×111113021332 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111304133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555651066 + 5555651067.

It is an arithmetic number, because the mean of its divisors is an integer number (5555651067).

Almost surely, 211111302133 is an apocalyptic number.

It is an amenable number.

11111302133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111302133 is an equidigital number, since it uses as much as digits as its factorization.

11111302133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11111302133 its reverse (33120311111), we get a palindrome (44231613244).

The spelling of 11111302133 in words is "eleven billion, one hundred eleven million, three hundred two thousand, one hundred thirty-three".