Base | Representation |
---|---|
bin | 10100101100100100… |
… | …10000001111110101 |
3 | 1001200100212122001122 |
4 | 22112102100033311 |
5 | 140223443132013 |
6 | 5034321433325 |
7 | 542230336601 |
oct | 122622201765 |
9 | 31610778048 |
10 | 11111302133 |
11 | 4792049828 |
12 | 21a119b845 |
13 | 1080cc75b9 |
14 | 7759a4501 |
15 | 450727a08 |
hex | 2964903f5 |
11111302133 has 2 divisors, whose sum is σ = 11111302134. Its totient is φ = 11111302132.
The previous prime is 11111302117. The next prime is 11111302157. The reversal of 11111302133 is 33120311111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8549221444 + 2562080689 = 92462^2 + 50617^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111302133 - 24 = 11111302117 is a prime.
It is a super-2 number, since 2×111113021332 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111304133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555651066 + 5555651067.
It is an arithmetic number, because the mean of its divisors is an integer number (5555651067).
Almost surely, 211111302133 is an apocalyptic number.
It is an amenable number.
11111302133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111302133 is an equidigital number, since it uses as much as digits as its factorization.
11111302133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11111302133 its reverse (33120311111), we get a palindrome (44231613244).
The spelling of 11111302133 in words is "eleven billion, one hundred eleven million, three hundred two thousand, one hundred thirty-three".
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