1111131200083 has 2 divisors, whose sum is σ = 1111131200084. Its totient is φ = 1111131200082.

The previous prime is 1111131200017. The next prime is 1111131200191. The reversal of 1111131200083 is 3800021311111.

It is a weak prime.

It is an emirp because it is prime and its reverse (3800021311111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111131200083 is a prime.

It is a super-2 number, since 2×1111131200083² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1111131200383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555565600041 + 555565600042.

It is an arithmetic number, because the mean of its divisors is an integer number (555565600042).

Almost surely, 2^{1111131200083} is an apocalyptic number.

1111131200083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111131200083 is an equidigital number, since it uses as much as digits as its factorization.

1111131200083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 1111131200083 its reverse (3800021311111), we get a palindrome (4911152511194).

The spelling of 1111131200083 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, two hundred thousand, eighty-three".