Base | Representation |
---|---|
bin | 10000001010110100100… |
… | …101001001101010111111 |
3 | 10221020000122101022210111 |
4 | 100022310211021222333 |
5 | 121201044041401231 |
6 | 2210240245450451 |
7 | 143163603240145 |
oct | 20126445115277 |
9 | 3836018338714 |
10 | 1111131200191 |
11 | 3992566604a1 |
12 | 15b417710a27 |
13 | 80a18c4b76c |
14 | 3bac996b595 |
15 | 1dd82d094b1 |
hex | 102b4949abf |
1111131200191 has 2 divisors, whose sum is σ = 1111131200192. Its totient is φ = 1111131200190.
The previous prime is 1111131200083. The next prime is 1111131200227. The reversal of 1111131200191 is 1910021311111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111131200191 - 211 = 1111131198143 is a prime.
It is a super-2 number, since 2×11111312001912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111131200591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555565600095 + 555565600096.
It is an arithmetic number, because the mean of its divisors is an integer number (555565600096).
Almost surely, 21111131200191 is an apocalyptic number.
1111131200191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111131200191 is an equidigital number, since it uses as much as digits as its factorization.
1111131200191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 22.
The spelling of 1111131200191 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, two hundred thousand, one hundred ninety-one".
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