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1111131281111 is a prime number
BaseRepresentation
bin10000001010110100100…
…101011101011011010111
310221020000122112102210112
4100022310211131123113
5121201044101443421
62210240251313235
7143163604025105
oct20126445353327
93836018472715
101111131281111
11399256706275
1215b41774b81b
1380a18c79547
143bac998cc75
151dd82d2345b
hex102b495d6d7

1111131281111 has 2 divisors, whose sum is σ = 1111131281112. Its totient is φ = 1111131281110.

The previous prime is 1111131281101. The next prime is 1111131281159. The reversal of 1111131281111 is 1111821311111.

It is a m-pointer prime, because the next prime (1111131281159) can be obtained adding 1111131281111 to its product of digits (48).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1111131281111 is a prime.

It is a super-2 number, since 2×11111312811112 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111131281101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555565640555 + 555565640556.

It is an arithmetic number, because the mean of its divisors is an integer number (555565640556).

Almost surely, 21111131281111 is an apocalyptic number.

1111131281111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111131281111 is an equidigital number, since it uses as much as digits as its factorization.

1111131281111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 23.

Adding to 1111131281111 its reverse (1111821311111), we get a palindrome (2222952592222).

The spelling of 1111131281111 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, two hundred eighty-one thousand, one hundred eleven".