Search a number
-
+
111113132120100 = 2232521121770984653
BaseRepresentation
bin11001010000111010001010…
…110001010001100000100100
3112120102022102020000101000100
4121100322022301101200210
5104030434143310320400
61032152400200144100
732255441665442535
oct3120721261214044
9476368366011010
10111113132120100
11324498a6406400
1210566577168030
1349ccc00929ba6
141d61c9352668c
15cca493012100
hex650e8ac51824

111113132120100 has 648 divisors, whose sum is σ = 405913097477160. Its totient is φ = 25315959398400.

The previous prime is 111113132120099. The next prime is 111113132120161. The reversal of 111113132120100 is 1021231311111.

111113132120100 is a `hidden beast` number, since 1 + 1 + 11 + 131 + 321 + 201 + 0 + 0 = 666.

It can be written as a sum of positive squares in 12 ways, for example, as 65537023104036 + 45576109016064 = 8095494^2 + 6751008^2 .

It is a super-2 number, since 2×1111131321201002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 1312529374 + ... + 1312614026.

It is an arithmetic number, because the mean of its divisors is an integer number (626409101045).

Almost surely, 2111113132120100 is an apocalyptic number.

111113132120100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111113132120100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (202956548738580).

111113132120100 is an abundant number, since it is smaller than the sum of its proper divisors (294799965357060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111113132120100 is a wasteful number, since it uses less digits than its factorization.

111113132120100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85421 (or 85400 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 111113132120100 its reverse (1021231311111), we get a palindrome (112134363431211).

The spelling of 111113132120100 in words is "one hundred eleven trillion, one hundred thirteen billion, one hundred thirty-two million, one hundred twenty thousand, one hundred".