1111131434020 has 48 divisors (see below), whose sum is σ = 2354528398320. Its totient is φ = 440425230336.

The previous prime is 1111131434011. The next prime is 1111131434051. The reversal of 1111131434020 is 204341311111.

It can be written as a sum of positive squares in 8 ways, for example, as 34534275556 + 1076597158464 = 185834^2 + 1037592^2 .

It is a super-2 number, since 2×1111131434020² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111131433982 and 1111131434000.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11044264 + ... + 11144416.

It is an arithmetic number, because the mean of its divisors is an integer number (49052674965).

Almost surely, 2^{1111131434020} is an apocalyptic number.

1111131434020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1111131434020 is an abundant number, since it is smaller than the sum of its proper divisors (1243396964300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111131434020 is a wasteful number, since it uses less digits than its factorization.

1111131434020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105184 (or 105182 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1111131434020 its reverse (204341311111), we get a palindrome (1315472745131).

The spelling of 1111131434020 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, four hundred thirty-four thousand, twenty".